()cookie、name、parameter或property属性之一指定的变量是否大于value属性指定的常量值logic。
第1题:
A.It must be the same as the server-name parameter on the LAC
B.It must be the same as the client-name arameteron the LAC
C.It must be the same as the remote-hostname parameter on the LAC
D.It must be the same as the tunnel password parameter on the LAC
第2题:
You are configuring the ERX Edge Router as an LNS in an L2TP network.Which statement is true about the value of the remote host parameter?()
第3题:
Given a web application in which the cookie userName is expected to contain the name of the user. Which EL expression evaluates to that user name?()
第4题:
在struts框架中,以下()语句可以输出Userbean(Bean对象名称为user)中name属性的值。
第5题:
Which property of the ListView class is used to get/set the name of the data field whose value exclusively identifes every data row of a ListView when the ClientIDMode property is set to Predictable?()
第6题:
GET_RELATION_PROPERTY
SET_RELATION_PROPERTY
GET_BLOCK_PROPERTY
GET_FORM_PROPERTY
第7题:
{ Binding Path=Data/Name, FallbackValue='N/A' }
{ Binding Path=Data.Name, FallbackValue='N/A' }
{ Binding Path=Data/Name, TargetNullValue='N/A' }
{ Binding Path=Data.Name, TargetNullValue='N/A' }
第8题:
第9题:
messagePresent
messageNotPresent
present
notPresent
第10题:
<c:set var=’order’ property=’shipAddress’value=’${client.homeAddress}’ />
<c:set target=’${order}’ property=’shipAddress’value=’${client.homeAddress}’ />
<jsp:setProperty name=’${order}’ property=’shipAddress’ value=’${client.homeAddress}’ />
<c:set var=’order’ property=’shipAddress’><jsp:getProperty name=’client’ property=’homeAddress’ /> </c:store>
<c:set target=’${order}’ property=’shipAddress’><jsp:getProperty name=’client’ property=’homeAddress’ /> </c:set>
第11题:
A subplan has the PLAN_SUB parameter value set to SUB
A top-level plan has the GROUP_OR_PLAN parameter set to the name of the subplan in the resource-plan definition
There is no difference in the resource-plan definition
A subplan always has the CPU_MTH parameter value set to RATIO
The string TOP_LEVEL is appended to the name of top-level resource plans
第12题:
Cookie cookie[]=request.getCookies()
Cookie cookie[]=request.addCookies()
response.addCookie(cookie)
Cookie c=new cookie(“name”,“value”)
以上选项都不能
第13题:
What is the name of the method that threads can use to pause their execution until signalled to continue by another thread? () Fill in the name of the method (do not include a parameter list).
第14题:
transition-property属性语法格式正确的是()。
第15题:
下面哪句代码能获得硬盘上所有的Cookie?()
第16题:
In a JSP-centric shopping cart application, you need to move a client’s home address of the Customerobject into the shipping address of the Order object. The address data is stored in a value object classcalled Address with properties for: street address, city, province, country, and postal code. Which two JSPcode snippets can be used to accomplish this goal?()
第17题:
You use Microsoft Visual Studio 2010 and Microsoft . NET Framework 4 to create a Windows Presentation Foundation (WPF) application. You create a WPF window in the application. You add the following code segment to the application. public class ViewModel { public CollectionView Data { get; set; } } public class BusinessObject { public string Name { get; set; } } The DataContext property of the window is set to an instance of the ViewModel class. The Data property of the ViewModel instance is initialized with a collection of BusinessObject objects. You add a TextBox control to the Window. You need to bind the Text property of the TextBox control to the Name property of the current item of the CollectionView of the DataContext object. You also need to ensure that when a binding error occurs, the Text property of the TextBox control is set to N/A . Which binding expression should you use?()
第18题:
- Specify a unique DiscoveryVersion parameter for each endpoint constructor. - Use the same value for the Address property of each endpoint.
- Use the endpoint constructor without the DiscoveryVersion parameter. - Use a unique value for the Address property of each endpoint.
- Specify a unique DiscoveryVersion parameter for each endpoint constructor. - Use a unique value for the Address property of each endpoint.
- Use the endpoint constructor without the DiscoveryVersion parameter. - Use the same value for the Address property of each endpoint.
第19题:
99
100
101
999
1000
第20题:
${resultMap[results[0].name] = results[0].score}
<c:set var=${resultMap} key=${results[0].name} value=${results[0].score} />
<c:set var=resultMap property=${results[0].name}> ${results[0].value}</c:set>
<c:set var=resultMap property=${results[0].name} value=${results[0].score} />
<c:set target=${resultMap} property=${results[0].name} value=${results[0].score} />
第21题:
greaterThan
greaterEqual
greater
parameter
第22题:
<bean:writeid=”user”property=”name”>
<bean:messageid=”user”property=”name”>
<bean:writename=”user”property=”name”>
<bean:messagename=”user”property=”name”>
第23题:
${userName}
${cookie.userName}
${cookie.user.name}
${cookies.userName[0]}