单选题When the average of a list of course grades is multiplied by the number of courses, the result is n. What does n represent?A Half the number of coursesB Half the sum of course gradesC The number of coursesD The average of the course gradesE The sum of

题目
单选题
When the average of a list of course grades is multiplied by the number of courses, the result is n. What does n represent?
A

Half the number of courses

B

Half the sum of course grades

C

The number of courses

D

The average of the course grades

E

The sum of the course grades


相似考题
参考答案和解析
正确答案: B
解析:
利用平均值的计算公式,分析题目中的数量关系,即可得出答案。
更多“单选题When the average of a list of course grades is multiplied by the number of courses, the result is n. What does n represent?A Half the number of coursesB Half the sum of course gradesC The number of coursesD The average of the course gradesE The sum of ”相关问题
  • 第1题:

    阅读下面程序

    import javax.swing.JOptionPane;

    public class Comparison {

    public static void main(String args[]) {

    String firstNumber, //用户输入第1个数据变量

    secondNumber, //用户输入第2个数据变量

    result; //输出结果变量

    int number1, //用于比较的第1个数

    number2; //用于比较的第2个数

    //用户输入第1个数据的字符串

    firstNuinber=JOptionPane.showInputDialog("输入第1个整数:");

    //用户输入第2个数据的字符串

    secondNumber=JOptionPane.showInputDialog("输入第2个整数:");

    //将字符串转换为整数类型

    number1=Integer.parseInt(firstNumber);

    number2=Integer.parseInt(secondNumber);

    //初始化结果变量

    ______

    //比较两个数据

    if(number1==number2)result+=number1+"=="+number2;

    if(number1! =number2) result+=number1+"!="+number2;

    if(number1<number2) result=result+"\n"+number1+"<"+number2;

    if(number1>number2) result=result+"\n"+number1+">"+number2;

    if(number1<=number2) result=result+"\n"+number1+"<="+number2;

    if(number1>=number2) result=result+"\n"+number1+">="+number2:

    //显示结果

    JOptionPane.showMessageDialog(null,result."比较结果",

    JOptionPane.INFORMATION_MESSAGE);

    System.exit(0);

    }

    }

    为使程序能正确运行并得到合理的输出结果,初始化结果变量语句(下画线处)应是

    A.result=" ";

    B.result=null

    C.result=number1

    D.result=number2


    正确答案:A
    解析:本程序是让用户输入两个数,然后对这两个数进行比较,最后输出比较结果。根据题目中的提示,下画线处的语句所完成的操作就是初始化result变量。因为result是一个字符串型变量,初始化就是要为其赋予一个字符型常量。选项B中的null不是字符串型数据。选项C和选项D均为整型数据,也不是字符串型数据。所以答案为A。

  • 第2题:

    EIGRP has been configured to opera te over Frame Relay multipoint connections. What should the bandwidth command be set to?()

    A. the CIR rate of the lowest speed connection multiplied by the number of circuits

    B. the CIR rate of the lowest speed connection

    C. the CIR rate of the highest s peed connection

    D. the sum of all the CIRs divided by the number of connections


    参考答案:A

  • 第3题:

    EIGRP has been configured to operate over Frame Relay multipoint connections. What should the bandwidth command be set to?()

    • A、the CIR rate of the lowest speed connection multiplied by the num ber of circuits
    • B、the CIR rate of the lowest speed connection
    • C、the CIR rate of the highest speed connection
    • D、the sum of all the CIRs divided by the number of connections

    正确答案:A

  • 第4题:

    The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12) SEMESTER_END DATE GPA NUMBER(4,3) The registrar has asked for a report on the average grade point average (GPA) for students enrolled during semesters that end in the year 2000. Which statement accomplish this? ()

    • A、SELECT AVERAGE(gpa) FROM student_grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';
    • B、SELECT COUNT(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';
    • C、SELECT MIN(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';
    • D、SELECT AVG(gpa) FROM student_grades WHERE semester _ end BETWEEN '01-JAN-2000' and '31-DEC-2000';
    • E、SELECT SUM(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';
    • F、SELECT MEDIAN(gpa) FROM student_grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';

    正确答案:D

  • 第5题:

    What does the number one 1 represent for interface fe-0/0/1?()

    • A、port number
    • B、PCI slot number
    • C、channel number
    • D、virtual PIC number

    正确答案:A

  • 第6题:

    Examine the description of the MARKS table: STD_ID NUMBER(4) STUDENT_NAME VARCHAR2(30) SUBJ1 NUMBER(3) SUBJ2 NUMBER(3) SUBJ3 NUMBER(3) SUBJ1, SUBJ2, and SUBJ3 indicate the marks (grades) obtained by a student in the three subjects. Which two statements are valid? ()

    • A、SELECT SUM(subj1, subj2, subj3) FROM marks;
    • B、SELECT SUM(subj1 + subj2 + subj3) FROM marks;
    • C、SELECT SUM(subj1), SUM(subj2), SUM(subj3) FROM marks;
    • D、SELECT MAX(subj1, subj2, subj3) FROM marks;
    • E、SELECT MINIMUM(subj1) FROM marks;
    • F、SELECT COUNT(std_id) FROM marks WHERE subj1 >= AVG(subj1);

    正确答案:B,C

  • 第7题:

    问答题
    What is the number that is one half of one quarter of one tenth of 400?

    正确答案: 5
    解析:
    400的十分之一是40,40的四分之一是10,10的二分之一是5。

  • 第8题:

    单选题
    What is the typical number of trunks in a Call Center?()
    A

    equal to half the number of IVR ports  

    B

    greater than the number of IVR ports plus the number of agent phones  

    C

    less than or equal to the number of IVR ports plus the number of agent phones  

    D

    twice the number of IVR ports plus the number of agent phones 


    正确答案: B
    解析: 暂无解析

  • 第9题:

    单选题
    What does the number one 1 represent for interface fe-0/0/1?()
    A

    port number

    B

    PCI slot number

    C

    channel number

    D

    virtual PIC number


    正确答案: A
    解析: 暂无解析

  • 第10题:

    单选题
    EIGRP has been configured to operate over Frame Relay multipoint connections. What should the bandwidth command be set to?()
    A

    the CIR rate of the lowest speed connection multiplied by the num ber of circuits

    B

    the CIR rate of the lowest speed connection

    C

    the CIR rate of the highest speed connection

    D

    the sum of all the CIRs divided by the number of connections


    正确答案: D
    解析: 暂无解析

  • 第11题:

    多选题
    View the Exhibit and examine the data in the PRODUCT INFORMATION table. Which two tasks would require subqueries? ()
    A

    displaying the minimum list price for each product status

    B

    displaying all supplier IDs whose average list price is more than 500

    C

    displaying the number of products whose list prices are more than the average list price

    D

    displaying all the products whose minimum list prices are more than the average list price of products having the product status orderable

    E

    displaying the total number of products supplied by supplier 102071 and having product status OBSOLETE


    正确答案: A,E
    解析: 暂无解析

  • 第12题:

    单选题
    A number a increased by 20% of a results in a number b. When b is decreased by 33(1/3)% of b, the result is c. The number c is what percent of a?
    A

    40%

    B

    60%

    C

    80%

    D

    120%

    E

    150%


    正确答案: C
    解析:
    If a increased by 20% of a results in b, then a + (20% of a) = b, a +0.2a =b, 1.2a = b. When b is decreased by 33(1/3)% of b, the result is c, so b - (1/3)b = (2/3)b = c. Since c = (2/3)b = (2/3)(1.2a) = 0.80a, then c is 80% of a.

  • 第13题:

    b)

    main()

    {

    union{ /*定义一个联合*/

    int i;

    struct{ /*在联合中定义一个结构*/

    char first;

    char second;

    }half;

    }number;

    number.i=0x4241; /*联合成员赋值*/

    printf("%c%c\n", number.half.first,

    mumber.half.second);

    number.half.first='a'; /*联合中结构成员赋值

    */

    number.half.second='b';

    printf("%x\n", number.i);

    getch();

    }


    正确答案:

     

    AB (0x41 对应'A',是低位;Ox42 对应'B',
    是高位)6261 (number.i 和number.half 共用一块地址空
    间)

  • 第14题:

    Zhang Jun's teacher suggests that he take a(n)__________language course to improve his English.

    A.intermediate
    B.middle
    C.medium
    D.average

    答案:A
    解析:
    考查近义词辨析。intermediate“中等程度的,中级的”,侧重难易程度;middle“中间的”,侧重方位和时间;medium“中等的,中号的(尺寸、数量、规模等)”,average“平均的;普通的,一般的”。根据旬意可知,张军的老师建议他参加一门中级水平的语言课程来提高他的英语水平。故选A。

  • 第15题:

    EIGRP has been configured to opera te over Frame Relay multipoint connections. What should the bandwidth command be set to?()

    • A、the CIR rate of the lowest speed connection multiplied by the number of circuits
    • B、the CIR rate of the lowest speed connection
    • C、the CIR rate of the highest s peed connection
    • D、the sum of all the CIRs divided by the number of connections

    正确答案:A

  • 第16题:

    在Excel2002中,AVERAGE(number1,number2,…)返回()。


    正确答案:参数的平均值

  • 第17题:

    What is the typical number of trunks in a Call Center?()

    • A、equal to half the number of IVR ports  
    • B、greater than the number of IVR ports plus the number of agent phones  
    • C、less than or equal to the number of IVR ports plus the number of agent phones  
    • D、twice the number of IVR ports plus the number of agent phones 

    正确答案:C

  • 第18题:

    单选题
    When the average of a list of course grades is multiplied by the number of courses, the result is n. What does n represent?
    A

    Half the number of courses

    B

    Half the sum of course grades

    C

    The number of courses

    D

    The average of the course grades

    E

    The sum of the course grades


    正确答案: E
    解析:
    利用平均值的计算公式,分析题目中的数量关系,即可得出答案。

  • 第19题:

    单选题
    The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12) SEMESTER_END DATE GPA NUMBER(4,3) The registrar has asked for a report on the average grade point average (GPA) for students enrolled during semesters that end in the year 2000. Which statement accomplish this? ()
    A

    SELECT AVERAGE(gpa) FROM student_grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';

    B

    SELECT COUNT(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';

    C

    SELECT MIN(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';

    D

    SELECT AVG(gpa) FROM student_grades WHERE semester _ end BETWEEN '01-JAN-2000' and '31-DEC-2000';

    E

    SELECT SUM(gpa) FROM student grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';

    F

    SELECT MEDIAN(gpa) FROM student_grades WHERE semester _ end > '01-JAN-2000' and semester end <31-DEC-2000';


    正确答案: A
    解析: 暂无解析

  • 第20题:

    单选题
    A

    The length of the course.

    B

    The route the cyclists take.

    C

    The number of participants.

    D

    The month in which the tour is held.


    正确答案: B
    解析:
    [考点]细节题。录音中女士明确提到了每年的路线不一样,答案为B项。

  • 第21题:

    填空题
    在Excel2002中,AVERAGE(number1,number2,…)返回()。

    正确答案: 参数的平均值
    解析: 暂无解析

  • 第22题:

    单选题
    If the sum of a number and the original number increased by 5 is greater than11, which could be a possible value of the number?
    A

    -5

    B

    -1

    C

    1

    D

    3

    E

    4


    正确答案: C
    解析:
    If the sum of a number, x, and the original number increased by 5, x+5, is greater than 11, then x+(x+5)>11, so 2x+5>11. Then 2x > 6, so x > 3. The only answer choice that is greater than 3 is E..

  • 第23题:

    单选题
    EIGRP has been configured to opera te over Frame Relay multipoint connections. What should the bandwidth command be set to?()
    A

    the CIR rate of the lowest speed connection multiplied by the number of circuits

    B

    the CIR rate of the lowest speed connection

    C

    the CIR rate of the highest s peed connection

    D

    the sum of all the CIRs divided by the number of connections


    正确答案: C
    解析: 暂无解析

  • 第24题:

    单选题
    The average (arithmetic mean) of a set of seven numbers is 81. If one of the numbers is discarded, the average of the remaining numbers is 78. What is the value of the number that was discarded?
    A

    98

    B

    99

    C

    100

    D

    101

    E

    102


    正确答案: B
    解析:
    If the average (arithmetic mean) of a set of seven numbers is 81, then the sum of these seven numbers is 7 x 81 or 567. Since, if one of the numbers is discarded, the average of the six remaining numbers is 78, the sum of these six numbers is 6×78 or 468. Since 567 - 468 = 99, the value of the number that was discarded is 99.