WHERE lower(country_address) = france
WHERE lower(country_address) = 'france'
WHERE lower(country_address) IS 'france'
WHERE lower(country_address) = '%france%'
WHERE lower(country_address) LIKE %france%
第1题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第2题:
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
第3题:
WHERE lower(country_address) = france
WHERE lower(country_address) = 'france'
WHERE lower(country_address) IS 'france'
WHERE lower(country_address) = '%france%'
WHERE lower(country_address) LIKE %france%
第4题:
SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;
SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';
SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;
SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;
SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
第5题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第6题:
SELECT city_address, COUNT(*) FROM customers WHERE city _ address IN ('Los Angeles','San Fransisco');
SELECT city_address, COUNT (*) FROM customers WHERE city address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address;
SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address, customer_ id;
SELECT city_address, COUNT (customer_id) FROM customers GROUP BY city_ address IN ('Los Angeles','San Fransisco');
第7题:
SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;
SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;
第8题:
SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;
SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;
第9题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第10题:
SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco');
SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address;
SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address, customer_id;
SELECT city_address, COUNT(customer_id) FROM customers GROUP BY city_address IN ('Los Angeles', 'San Francisco');
第11题:
CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status NUMBER(10) DEFAULT 'PENDING', date_ordered DATE );
CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );
CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );
CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );
CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );
CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered VARCHAR2 );
第12题:
SELECT TOTAL(*) FROM customer;
SELECT COUNT(*) FROM customer;
SELECT TOTAL(customer_id) FROM customer;
SELECT COUNT(customer_id) FROM customer;
SELECT COUNT(customers) FROM customer;
SELECT TOTAL(customer_name) FROM customer;
第13题:
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
第14题:
COUNT(UPPER(country_address))
COUNT(DIFF(UPPER(country_address)))
COUNT(UNIQUE(UPPER(country_address)))
COUNT DISTINCT UPPER(country_address)
COUNT(DISTINCT (UPPER(country_address)))