It is better to accept something small than to reject it and hope to get more later on.A、A bird in the hand is worth two in the bush.B、A goose in the hand is worth two in the bush.C、A frog in the hand is worth a swan in the sky.D、A fish in the pot is wort

题目
It is better to accept something small than to reject it and hope to get more later on.

A、A bird in the hand is worth two in the bush.

B、A goose in the hand is worth two in the bush.

C、A frog in the hand is worth a swan in the sky.

D、A fish in the pot is worth two in the water.


相似考题
更多“It is better to accept something small than to reject it and hope to get more later on. ”相关问题
  • 第1题:

    Given the following policy, what happens when the 1.1/17 route is evaluated?()[edit policy-options] policy-statement test{ from { route-filter 0/0 orlonger accept; route-filter 1.1/17 upto /24 reject; route-filter 1.1/18 exact; }then { metric 6; accept; }

    A. The route does not match this policy.

    B. The route is accepted.

    C. The route is rejected.

    D. The route is accepted with a metric of 6.


    参考答案:A

  • 第2题:

    下列方法中,javA.net.ServerSocket类用于接收客户端请求的方法是()

    A.get()

    B.accept()

    C.receive()

    D.connect()


    答案:B

  • 第3题:

    中国青少年发展基金会在网上的主页地址是()。

    A.http://project-hopE.cydF.gov.cn

    B.http://project-hopE.cydF.ac

    C.http://project-hopE.cydF.edu.cn

    D.http://project-hopE.cydF.com.cn


    参考答案:C

  • 第4题:

    WhichactionoccurswhentheBGProute20.1.0.0/16isevaluatedbythepolicyexpression?()[editpolicy-options]policy-statementreject_10{from{route-filter20.1.0.0/16orlongerM}then{communityadd90-1;accept}}policy-statementaccept_20{from{route-filter20.1.0.0/16orlongerM}then{communityadd100-1;reject;}}community100-1members100:1;community90-1members90:1[editprotocols]bgp{groupebgp-group{neighbor172.16.201.1{export(reject-10&&accept-20);}}}

    A.Therouteisnotannounced.

    B.Therouteisannouncedwith90:1added.

    C.Therouteisannouncedwith100:1added.

    D.Therouteisannouncedwithcommunities90:1and100:1added.


    参考答案:A

  • 第5题:

    阅读以下说明和Java程序,将应填入(n)处的字句写在对应栏内。

    [说明]

    下面程序输出一个矩形面积,以及矩形区域上的假想的作物产量。

    [Java程序]

    public class MainJava {

    public static void main(String[] args){

    Lot_size small=new Lot_size();

    Lot_size medium=new Lot_size();

    small.set(5,5,5,25);

    medium.set(10,10,10,50);

    System.out.println("For a small lot of area"

    +small.get_area()+"\n");

    System.out.println("the actual crops are $"

    +small.get_data2()+"\n");

    System.out.println("and ideal crops are $"

    +small.get data()+"\n");

    System.out.println("For a medium lot of area"

    +medium.get_area()+“\n”);

    System.out.println("the actual crops are $"

    +medium.get_data2()+"\n");

    System.out.println ("and ideal crops are $"

    +medium.get_data()+"\n");

    }

    }

    class Crop_assessment{

    private int actual_crop;

    private int ideal_crop;

    public void set(int in_actual,int in ideal){

    actual_crop=in_actual;

    ideal_crop=in_ideal;

    }

    public int get_actual_crop(){return (1) ;}

    public int get_ideal_crop()(return (2) ;}

    }

    class Lot_size{

    private int length;

    private int width;

    private Crop_assessment crop= (3) ;

    public void set(int 1,int W,int a,int i){

    length=1;

    width=W;

    crop.set(a,i);

    }

    public int get_area(){return length*width;}

    public int get_data()freturn (4) ;}

    public int get_data2()(return (5) ;}

    }


    正确答案:(1) return actual_crop (2) return ideal_crop (3) new Crop_assessment() (4) crop.get_ideal_crop (5) crop.get_actual_crop()
    (1) return actual_crop (2) return ideal_crop (3) new Crop_assessment() (4) crop.get_ideal_crop (5) crop.get_actual_crop() 解析:本题以Java语言为载体,考查面向对象程序设计中的几个重要概念—类的嵌套及函数的使用。
    本题的功能是通过已定义的粮食收成类定义了一个计算特定矩形域上粮食收成的类,在主函数中定义了两个对象,并调用了相应的函数,来输出理想和实际的粮食产量。
    首先,由于Crop assessment定义的成员数据缺省为私有的,所以想要获得实际和理想的粮食产量,要通过两个公有成员函数,所以(1)处应填入“return actual_crop”,(2)处应填入“return ideal_crop”。
    其次,在类Lot size中,由于我们要反映矩形域上的粮食产量,所以我们在类中嵌套定义了一个类,Java中对象需要实例化,故(3)应填入“new Crop_assessment()”。
    最后,由于我们想通过Lot_size类中的get_data和get_data2函数得到粮食产量,但由于这两个成员数据是私有函数,所以我们必须通过定义的对象调用它,所以(4)应填入“crop.get_ideal_crop()”,(5)应填入“crop.get_actual_crop()”。

  • 第6题:

    Which of the following shows the correct sentence stress in normal cases


    A.His 'brother is my 'best Mend.

    B.They 'help one 'another in their work.

    C.They have 'been in the 'countryside recently.

    D.She 'thought herself 'better 'than 'anyone else.

    答案:A
    解析:
    考查句子重读规则。在英语连贯的说话和朗读中,有些词说得或读得又轻又快,而且较为含糊。有些词则说得或读得又重又慢,而且较为清晰。那些说得或读得响亮而清晰的词就是句子重音所在。一般来说,在句子中需重读的词都是实词,比如.名词、动词(除be动词和助动词外)、形容词、副词、指示代词等;不重读的多为虚词,比如,冠词、连词、介词、人称代词、相互代词等。但这也不是绝对的,一个词在句中重读与否,同它在句中所起的意义和作用有密切的关系。B、C、D三项中均有不属于重读范围的词。即B项one another是相互代词,C项been是be动词的过去分词形式,D项than是介词。故选A。