how many seats in the house of commons should a party hold at least in order to win the election?
A. 351
B. 326.
C. 651.
D. 626.
第1题:
下面是一个Applet程序,其功能是实现一个计数器,每隔0.15秒计数器数值加1,数值动态变化,并且能够控制计数器的暂停和继续。要求通过使用Swing的构件建立图形用户界面。主要包括一个文本区域,用于显示计数器结果:两个按钮,一个使计数器暂停,一个使计数器继续工作。请改正程序中的错误(有下划线的语句),使程序能输出正确的结果。
注意:不改动程序的结构,不得增行或删行。
源程序文件代码清单如下。
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
/*
<applet code="ex19_3.class" width=800 height=400>
</applet>
*/
public class ex19_3 extends JApplet
{
private JTextField jtf=new JTextField(15);
private JButton Hold=new JButton("Hold");
private JButton resume=new JButton("Resume");
private ex19_3th obj19_3th=new ex19_3th();
class ex19_3th extends Thread
{
private int cnt=0;
private boolean bIsHold=false;
public ex19_3th() {start();}
public void hold()
{
bIsHold=true;
}
public synchronized void fauxResume()
{
bIsHold=false;
wait ();
}
public void run()
{
while (true)
{
try {
sleep(150);
synchronized(this)
{
while(bIsHold)
notify();
}
}catch(InterruptedException ie)
{
System.err.println("Interrupted");
}
jtf.setText(cnt);
}
}
}
public void init()
{
Container cp=getContentPane();
cp.setLayout(new FlowLayout());
cp.add(jtf);
Hold.addActionListener(
new ActionListener()
{
public void actionPerformed(ActionEvent ae)
{
obj19_3th.hold ( );
}
});
cp.add(Hold);
resume.addActionListener
(
new ActionListener()
{
public void actionPerformed(ActionEvent e)
{
obj19_3th.fauxResume();
}
&n
第2题:
有如下类定义: class Point{ private: static int how_many; }; ___________how_many=0; 要初始化Point类的静态成员how_many,下画线处应填入的内容是( )。
A.int
B.static int
C.int Point::
D.static int Point::
第3题:
______ it rain tomorrow moring, the loading ______.
A.Should / will be postponed
B.If / shall be postponed
C.Should / would be postponed
D.If / has to be postponed
第4题:
有如下类定义: class Point{ private: static int how_many; }; ______how_many=0; 要初始化Point类的静态成员how_many,下划线处应填入的内容是
A.int
B.static int
C.int Point: :
D.static int Point
第5题:
A. many - to - one
B. one - to - one
C. one - to - many
D. many - to - many
第6题: