更多“They always kept on good ( ) with their next-door neighbors for the children’s sake. ”相关问题
  • 第1题:

    设s1="GOOD",s2="-",s3="BYE!",则s1、s2和s3连接后的结果是()

    A、"GOOD-BYE!"

    B、"GOODBYE!"

    C、"GOODBYE!"

    D、"GOODBYE"


    参考答案:A

  • 第2题:

    以下能正确进行字符串赋值、赋初值的语句是______。

    A.char s[5]:{'a','e','i','o','u'};

    B.char *s; s="good";

    C.char s[5]="good";

    D.char s[5]; s="good";


    正确答案:C

  • 第3题:

    下列Moore型状态机采用Verilog语言主控时序部分正确的是:

    A.always@(posedge clk or negedge reset) begin if(!reset) current_state<=s0; else current_state<=next_state; end

    B.always@(posedge clk ) begin if(!reset) current_state<=s0; else current_state<=next_state; end

    C.always@(posedge clk t) if(reset) current_state<=s0; else current_state<=next_state;

    D.always@(posedge clk or negedge reset) if(reset) current_state<=s0; else current_state<=next_state;


    always@(posedge clk or negedge reset) begin if(!reset) current_state<=s0; else current_state<=next_state; end

  • 第4题:

    下列哪个程序段可能导致错误?

    A.String s="hello"; String t= "good"; String k=s+ t;

    B.String s="hello"; String t; t=s[3]+"one";

    C.String s="hello"; String standard=s. toUpperCase

    D.String s="hello"; String t =s+ "good"


    正确答案:B
    解析:选项A)String类型可以直接使用“+”运算符进行连接运算。选项B)String是一种Object,而不是简单的字符数组,不能使用下标运算符取其值的某个元素,错误。选项C)toUpperCase()方法是String对象的一个方法,作用是将字符串的内容全部转换为大写并返回转换后的结果(String类型)。选项D)同选项A)。

  • 第5题:

    4、以下的描述中,必然是对Mealy型状态机的描述的是?

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……

  • 第6题:

    以下的描述中,必然是对Mealy型状态机的描述的是?

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……