An administrator account is granted the CREATE SESSION and SET CONTAINER system privileges.A multitenant container database (CDB) instant has the following parameter set:THREADED_EXECUTION = FALSEWhich four statements are true about this administrator est

题目

An administrator account is granted the CREATE SESSION and SET CONTAINER system privileges.A multitenant container database (CDB) instant has the following parameter set:THREADED_EXECUTION = FALSEWhich four statements are true about this administrator establishing connections to root in a CDB that has been opened in read only mode?()

A. You can conned as a common user by using the connect statement.

B. You can connect as a local user by using the connect statement.

C. You can connect by using easy connect.

D. You can connect by using OS authentication.

E. You can connect by using a Net Service name.

F. You can connect as a local user by using the SET CONTAINER statement.


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  • 第1题:

    Whichtwobuilt-inswouldyouusetoremovetheHOUR_ALARMtimerusingthetimer_idparameter?()

    A.FIND_TIMER

    B.CREATE_TIMER

    C.SET_TIMER

    D.DELETE_TIMER

    E.GET_APPLICATION_PROPERTY


    参考答案:A, D

  • 第2题:

    以下程序的输出结果是_____。 include class object {private:int val; public:objec

    以下程序的输出结果是_____。

    include<iostream.h>

    class object

    { private:

    int val;

    public:

    object( ) ;

    object(int i) ;

    ~object( ) ;};

    object: :object( )

    { val=0;

    cout < < "Default constructor for object" < < endl;}

    object: :object(int i)

    { val=i;

    cout < < "Constructor for object" < < val < < endl;}

    object: :~object( )

    { cout < < "Destructor for object" < < val < < endl;}

    class container{ private:

    object one;

    object two;

    int data;

    public:

    container( ) ;

    container(int i,int j,int k) ;

    ~container( ) ;};

    container: :container( )

    { data=0;

    cout < < "Default constructor for container" < < endl;}

    container: :container(int i,int j,int k) :two(i) ,one(j)

    { data=k;

    cout < < "Constructor for container" < < endl;}

    container: :~container( )

    { cout < < "Destructor for container" < < endl;}

    void main( )

    { container anObj(5,6,10) ;}


    正确答案:Constructor for object6 Constructor for object5 Constructor for container Destructor for container Destructor for object5 Destructor for object6
    Constructor for object6 Constructor for object5 Constructor for container Destructor for container Destructor for object5 Destructor for object6 解析:C++语言中的构造函数和析构函数分别是在声明对象时和对象调用完毕后调用,本题中的调用就是这样成对出现的。

  • 第3题:

    Examinethecode:CREATEROLEreadonlyIDENTIFIESUSINGapp.chk_readwrite;CREATEROLEreadwriteIDENTIFIEDUSINGapp.chk_readwrite;CREATEORREPLACEPROCEDUREapp.chk_readwriteAUTHIDCURRENT_USERISipchkSTRING(30);BEGINIFsys_context(‘USERENV’,’ISDBA’)=’TRUE’THENDBMS_SESSION.SET_ROLE‘READWRITE’);ELSEDBMS_SESSION.SET_ROLE(‘READONLY’);END;/WhichthreestatementscorrectlydescribetheSecureApplicationroledefinition?()

    A.Nouserorapplicationhastorememberorhideapassword.

    B.ItpreventseveryoneexceptatrueDBAsessionfromacquiringtheREADWRITErole.

    C.app.chk_readwriteiscalledwheneverausertriestoaccessrowsprotectedbytheREADONLYorREADWRITElabel.

    D.app.chk_readwriteiscalledbyusersorapplicationswhentheywanttoenabletheREADONLYor READWRITErole.


    参考答案:A, B, D

  • 第4题:

    A new report process containing a complex query is written, with high impact on the database. You wantto collect basic statistics about query, such as the level of parallelism, total database time, and the number of I/O requests.For the database instance STATISTICS_LEVEL, the initialization parameter is set to TYPICAL and theCONTROL_MANAGEMENT_PACK_ACCESS parameter is set to DIAGNOSTIC+TUNING.What should you do to accomplish this task?()

    A. Execute the query and view Active Session History (ASH) for information about the query.

    B. Enable SQL trace for the query.

    C. Create a database operation, execute the query, and use the DBMS_SQL_MONITOR. REPORT_SQL_MONITOR function to view the report.

    D. Use the DBMS_APPLICATION_INFO.SET_SESSION_LONGOPS procedure to monitor query execution and view the information from the V$SESSION_LONGOPS view.


    参考答案:C

  • 第5题:

    You are the administrator of a Windows Server 2003 computer named Testking1.Backups of the System State data of Testking1 occur each day by using the localAdministrator account.A new requirement restricts you from running services by using theAdministrator account. To meet the requirement, you create a new service accountnamed BackupTestking1 to be used for backups. You want this account to have theminimum permissions necessary to perform backups.You need to grant the appropriate permissions to the BackupTestking1 account andto configure the backup job to use the BackupTestking1 account.What should you do?()

    A. Add the BackupTestking1 account to the Server Operators group. Modify the backup Scheduled Task to use the BackupTestking1 account.

    B. Add the BackupTestking1 account to the Backup Operators group. Modify the backup Scheduled Task to use the BackupTesking1 account.

    C. Add the BackupTestking1 account to the Server Operators group. Modify the Task Scheduler service to use the BackupTestking1 account.

    D. Add the BackupTestking1 account to the Backup Operators group. Modify the Task Scheduler service to use the BackupTestking1 account.


    参考答案:B

  • 第6题:

    使用snmptuil.exe 可以查看代理的 MiB对象,下列文本框内oid部分是( ).C:\ Users\Administrator> snmptuil get 192.168.1.31 public.1.3.6.1.2.1.1.3.0Variable=system.sysUpTime.0Value=TimeTicks 1268830

    A.192.168.1.31
    B.1.3.6.1.2.1.1.3.0
    C.system.sysUpTime.0
    D.TimeTicks 1268803

    答案:B
    解析:
    C:\>snmputil get 192.168.1.31 public .1.3.6.1.2.1.1.3.0public .1.3.6.1.2.1.1.3.0是指的系统开机时间多长。OID(对象标识符),是SNMP代理提供的具有唯一标识的键值。MIB(管理信息基)提供数字化OID到可读文本的映射。所有完全验证OID都有 .iso.org.dod.internet.private 开始,数字表达为: .1.3.6.4. 。几乎所有的OID都会跟上企业(.1)和由IANA(互联网编号分配中心分配的)唯一的厂商标号。 OID的相对格式,从企业值开始,略过所有的隐含地址。因此,可以用相对地址 enterprises.netapp.netappl.raid.diskSUmmary.diskSpaceCount.0 来表示上述的OID,或者用数字格式 .1.789.6.4.8.0 .某些唯一键值,可用多个实例表示,这样所有的OID都以实例值结尾。因此可以看到大多数OID都是以一个 .0 结尾的。