Youexecutethefollowingcommandtocreatetwoconsumergroups,FIN_GROUP1andPAY_GROUP1,foraplan,PROD_PLAN:BEGINDBMS_RESOURCE_MANAGER.CREATE_SIMPLE_PLAN(SIMPLE_PLAN=>’prod_plan’,CONSUMER_GROUP1=>’fin_group1’,GROUP1_CPU=>80,CONSUMER_GROUP2=>’pay_group1’,GROUP2_CPU=

题目

Youexecutethefollowingcommandtocreatetwoconsumergroups,FIN_GROUP1andPAY_GROUP1,foraplan,PROD_PLAN:BEGINDBMS_RESOURCE_MANAGER.CREATE_SIMPLE_PLAN(SIMPLE_PLAN=>’prod_plan’,CONSUMER_GROUP1=>’fin_group1’,GROUP1_CPU=>80,CONSUMER_GROUP2=>’pay_group1’,GROUP2_CPU=>20)ENDWhichthreestatementsaretrue?()

A.SYS_GROUPgets100%CPUresourcesatlevel1.

B.FIN_GROUP1gets80%CPUresourcesatlevel1.

C.FIN_GROUP1gets80%CPUresourcesatlevel2.

D.PAY_GROUP1gets20%CPUresourcesatlevel1.

E.PAY_GROUP1gets20%CPUresourcesatlevel2.

F.OTHER_GROUPgets100%CPUresourcesatlevel1.

G.OTHER_GROUPgets100%CPUresourcesatlevel2.


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  • 第1题:

    向建立好的单向链表中的结点pr后插入一个新结点p,且所有结点都已具有如下形式的结构定义: struct node { int data; struct node *next; }*p, *pr, *head; 则操作正确的是

    A.p->next = pr->next; pr->next = p;#B.struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;#C.pr->next = p;#D.p->next = pr->next; pr = p;#E.pr->next = p; p->next = pr->next;
    p->next = pr->next; pr->next = p;;struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;

  • 第2题:

    4段速由RM、RL同时接通,由什么设定频率?

    A.PR4

    B.PR5

    C.PR6

    D.PR24


    D

  • 第3题:

    8、向建立好的单向链表中的结点pr后插入一个新结点p,且所有结点都已具有如下形式的结构定义: struct node { int data; struct node *next; }*p, *pr, *head; 则操作正确的是

    A.p->next = pr->next; pr->next = p;#B.struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;#C.pr->next = p;#D.p->next = pr->next; pr = p;#E.pr->next = p; p->next = pr->next;
    p->next = pr->next; pr->next = p;;struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;

  • 第4题:

    在定温下,同成分的两个大小不同的液滴的饱和蒸气压pr,1*(大液滴)和pr,2* (小液滴)存在的关系为:

    A.pr,1* > pr,2*

    B.pr,1*= pr,2*

    C.pr,1* < pr,2*

    D.不能确定


    P*(大液滴)小于P*(小液滴)

  • 第5题:

    9、向建立好的单向链表中的结点pr后插入一个新结点p,且所有结点都已具有如下形式的结构定义: struct node { int data; struct node *next; }*p, *pr, *head; 则操作正确的是

    A.p->next = pr->next; pr->next = p;#B.struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;#C.pr->next = p;#D.p->next = pr->next; pr = p;#E.pr->next = p; p->next = pr->next;
    p->next = pr->next; pr->next = p;;struct node * pTemp; pTemp = pr->next; pr->next = p; p->next = pTemp;