Which RADIUS configuration command implements a primary/backup scenario for multiple servers?()A.radius algorithm directB.radius algorithm backupC.radius algorithm primaryD.radius algorithm round-robin

题目
Which RADIUS configuration command implements a primary/backup scenario for multiple servers?()

A.radius algorithm direct

B.radius algorithm backup

C.radius algorithm primary

D.radius algorithm round-robin


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更多“Which RADIUS configuration command implements a primary/backup scenario for multiple servers?() ”相关问题
  • 第1题:

    邻区配置工具的入口菜单为_________.

    A、Configuration ->Wireless Config Application ->NE Relation Management

    B、Configuration ->Wireless Config Application ->Inter Me Configuration Import and Export

    C、Configuration ->Wireless Config Application ->Cell Tool

    D、Configuration ->NE Management


    标准答案:A

  • 第2题:

    An administrator wants to restore the /etc/resolv.conf file from a mksysb backup onto server1. After the mksysb is mounted in /mnt/backup/ from the local nim server.Which command should be run to restore the file?()

    A.tar -xvf /mnt/backup/server1.mksysb ./etc/resolv.conf

    B.restore -Tvf /mnt/backup/server1.mksysb ./etc/resolv.conf

    C.listvgbackup -f /mnt/backup/server1.mksysb -r ./etc/resolv.conf

    D.restorevgfiles -xrm /mnt/backup/server1.mksysb ./etc/resolv.conf


    参考答案:C

  • 第3题:


    A. same
    B. different
    C. single
    D. multiple

    答案:A
    解析:

  • 第4题:

    WhatDHCPoptioncanbesetonaISCDHCPservertotellNETBIOSclientsthattheWINSserverhastheIPaddress192.168.1.2?()

    A.optionnetbios-wins-servers192.168.1.2;

    B.optionwins-netbios-servers192.168.1.2;

    C.optionwins-name-servers192.168.1.2;

    D.optionnetbios-name-servers192.168.1.2;


    参考答案:D

  • 第5题:

    阅读以下说明和Java程序,填写程序中的空(1)~(6),将解答写入答题纸的对应栏内。
    【说明】
    以下Java代码实现一个简单绘图工具,绘制不同形状以及不同颜色的图形。部分接口、类及其关系如图5-1所示。




    【Java代码】
    interface?DrawCircle?{? //绘制圆形 public(1) ;}class?RedCircle?implements?DrawCircle?{? ?//绘制红色圆形???????public?void?drawCircle(int?radius,intx,?int?y)??{????????????System.out.println("Drawing?Circle[red,radius:"?+?radius?+",x:"?+?x?+?",y:"?+y+?"]");???????}}class?GreenCircle?implements?DrawCircle?{????//绘制绿色圆形??????public?void?drawCircle(int?radius,?int?x,int?y)?{???????????System.out.println("Drawing?Circle[green,radius:"?+radius+",x:?"?+x+?",y:?"?+y+?"]");??????}}abstract?class?Shape?{????//形状? protected? ? (2)???;? ? public?Shape(DrawCircle?drawCircle)?{? ?this.drawCircle=?drawCircle;? ? ? public?abstract?void?draw();}class?Circle?extends?Shape?{? //圆形? ?private?int?x,y,radius;? public?Circle(int?x,int?y,intradius,DrawCircle?drawCircle)?{? ?(3)???;? this.x?=?x;? ? ? this.y?=?y;? ?this.radius?=radius;? }? ? ?public?void?draw()?{? ? drawCircle.? ?(4)? ?;? ? ? }}public?class?DrawCircleMain?{? public?static?void?main(String[]?args)?{? Shape?redCircle=new?Circle(?100,100,10,? (5) );//绘制红色圆形? Shape?greenCircle=new?Circle(200,200,10,(6) );//绘制绿色圆形? ?redCircle.draw(); greenCircle.draw();? ?}}


    答案:
    解析:
    (1)void drawCircle (int radius,int x,int y)
    (2)DrawCircle drawCircle
    (3)super.drawcircle=drawcircle
    (4)drawCircle(radius,x,y)
    (5)new RedCircle()
    (6)new GreenCircle()【解析】
    第一空是填接口里面的方法,在接口的实现里面找,可以发现应该填void drawCircle (int radius,int x,int y)。
    第二空可以根据后面this drawCircle=drawCircle判断,这里应该有一个drawCircle属性,因此应该填)DrawCircle drawCircle。
    第三空这里用super,用super. drawcircle来引用父类的成员。
    第四空调用drawCircle(radius,x,y)方法。
    第五、六空分别创建一个红色圆形对象和一个绿色圆形对象作为Circle里面的实参。

  • 第6题:

    6、下列哪个选项是判断半径是不是正的,并求出圆的面积?

    A.if radius != 0: print(radius * radius * 3.14159)

    B.if radius >= 0: print(radius * radius * 3.14159)

    C.if radius < 0: print(radius * radius * 3.14159)

    D.if radius <= 0: print(radius * radius * 3.14159)


    Ba