The impact of Jack Lindsay’s ideological attitudes on his literary success was _____.［A］utterly negative［B］limited but indivisible［C］obviously positive［D］obscure in net effect
题目
The impact of Jack Lindsay’s ideological attitudes on his literary success was _____.
［A］utterly negative
［B］limited but indivisible
［C］obviously positive
［D］obscure in net effect
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更多“The impact of Jack Lindsay’s ideological attitudes on his literary success was ____ ”相关问题
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第1题：
下列语句中，不正确的是______。
A．static char a[]={"Jack"};
B．static char a[]="Jack";
C．printf("%s",a[0]);
D．scanf("%s",a);
正确答案：C
解析：当用%s格式符输出字符串时，printf中的输出项是字符数组名，不是数组元素名。 -
第2题：
A（ ）translation is not always the closest to the original meaning.A.literal
B.liberal
C.literate
D.literary答案：A解析：literal“文字的，字面的”，a literal translation直译。句意：直译未必最接近原义。这组词的拼写很相似，要注意其拼写上的细微差别。B.liberal“慷慨的，大方的，开明的”；C.literate“识字的，有文化的”；D.literary“文学（上）的”。 -
第3题：
以下关于Python自带数据结构的运算结果中正确的是哪一项？
A．.scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; del scores['Bill']; len(scores)的结果是6。
B．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; s = dict(Jack=90, Mike=80, Jay=85, Bill=60); 则scores == s 判断结果是False。
C．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; 无法执行命令 scores['Bill']=90; 因为原来的字典中已经有了一个值为90了。
D．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; sorted(scores.keys())的运算结果是 ['
D -
第4题：
A
In a small village， there is a teacher， a nurse(护士) ，a driver(司机) and a worker．They are good friends． What are their names? One is Mike， one is Jack， one is Tom and the other is John． Mike's， Jack’s and Tom-s children are classmates． John doesn’t have any children He teaches his friends' children at school． Mike has many hens． He gives the driver and the nurse eggs． Jack's child goes to the nurse- s house． The nurse-s house is beside Jack's．
( )21． Are the four people good friends?
A． Yes．
B． No．
C． Not．
D． They are brothers．
正确答案：A
21．A【解析】根据文章的第二句可知。 -
第5题：
HIS颜色模型中的S表示饱和度。（）
正确 -
第6题：
以下关于Python自带数据结构的运算结果中正确的是哪一项？
A．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; del scores['Bill']; len(scores)的结果是6。
B．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; s = dict(Jack=90, Mike=80, Jay=85, Bill=60); 则scores == s 判断结果是False。
C．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; 无法执行命令 scores['Bill']=90; 因为原来的字典中已经有了一个值为90了。
D．scores = {'Jack': 90, 'Mike': 80, 'Jay': 85, 'Bill': 60}; sorted(scores.keys())的运算结果是 ['B
D