Another aspect of C that's worth mentioning here is that it is, to put it bluntly, a bit dangerous. C does not, in general, try hard to protect a programmer from mistakes. If you write a piece of(66)which will(through some oversight of yours)do something

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Another aspect of C that's worth mentioning here is that it is, to put it bluntly, a bit dangerous. C does not, in general, try hard to protect a programmer from mistakes. If you write a piece of(66)which will(through some oversight of yours)do something wildly different from what you intended it to do, up to and including(67)your(68)or trashing your(69), and if it is possible for the(70)to compile it, it generally will. You wont get warnings of the form. "Do you really mean to... ?" or "Are you sure you really want to... ?". C is often compared to a sharp knife :' it can do a surgically precise job on some exacting task you have in mind, but it can also do a surgically precise job of cutting off your finger. It's up to you to use it carefully.

A.word

B.code

C.sentence

D.character


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更多“Another aspect of C that's worth mentioning here is that it is, to put it bluntly, a bit d ”相关问题
  • 第1题:

    以下属于TD-LTE高速率、高效率的是()

    A、高速率下行:80Mbps上行:50Mbps;高速率下行:5bit/s/Hz,上行:3bit/s/Hz

    B、高速率下行:100Mbps上行:60Mbps;高速率下行:6bit/s/Hz,上行:2.5bit/s/Hz

    C、高速率下行:80Mbps上行:50Mbps;高速率下行:6bit/s/Hz,上行:3bit/s/Hz

    D、高速率下行:100Mbps上行:50Mbps;高速率下行:5bit/s/Hz,上行:2.5bit/s/Hz


    参考答案:D

  • 第2题:

    已知某二进制系统的码元速率为2000波特,则该系统的传信率为多少? 若保持传码率保持不变,系统传输八进制信号,此时系统的传信率为多少?

    A.2000 bit/s;6000 bit/s

    B.2000 bit/s;3000 bit/s

    C.2000 bit/s;4000 bit/s

    D.2000 bit/s;8000 bit/s


    2 000 bit/s ; 6000 bit/s

  • 第3题:

    采用BPSK调制,升余弦滚降系数a=0.2,则信号的频带利用率为

    A.1bit/s/Hz

    B.1.67bit/s/Hz

    C.0.5bit/s/Hz

    D.0.83bit/s/Hz


    1/1.2

  • 第4题:

    7、已知某二进制系统的码元速率为2000波特,则该系统的传信率为多少? 若保持传码率保持不变,系统传输八进制信号,此时系统的传信率为多少?

    A.2000 bit/s;6000 bit/s

    B.2000 bit/s;3000 bit/s

    C.2000 bit/s;4000 bit/s

    D.2000 bit/s;8000 bit/s


    2 000 bit/s; 6000 bit/s

  • 第5题:

    若通信系统传码率RB=2400Baud,对于二进制信号,系统传信率为 bit/s;对于四进制,系统传信率为 bit/s。

    A.2400 bit/s 4800 bit/s

    B.2400 bit/s 2400 bit/s

    C.4800 bit/s 4800 bit/s

    D.4800 bit/s 2400 bit/s


    2400 bit/s 4800 bit/s

  • 第6题:

    已知某二进制系统的码元速率为2000波特,则该系统的传信率为多少? 若保持传码率保持不变,系统传输八进制信号,此时系统的传信率为多少?

    A.2000 bit/s;8000 bit/s

    B.2000 bit/s;6000 bit/s

    C.2000 bit/s;3000 bit/s

    D.2000 bit/s;4000 bit/s


    (1)二进制信息源的最大熵H(x)=log 2 2=1(bit/符号) 平均信息速率:R b =R BN ×H(x)=2400(bit/s) (2)十六进制信息源的最大熵:H(x)=log 2 16=4(bit/符号) 平均信息速率:R b =R BN ×H(x)=9600(bit/s)[知识点窍] 信息源泉的最大熵:H(x)=log 2 n(bit/符号) 信息速率:R b =R BN ×H(x)(bit/s) [逻辑推理] 计算得出二进制信息源最大熵H(x);通过已知码元速率R BN ,算出信息速率。