The 213.115.77.0 network was subnetted using a /28 subnet mask. How many usable subnets and host addresses per subnet were created as a result of this?A. 2 networks with 62 hostsB. 6 networks with 30 hostsC. 16 networks and 16 hostsD. 62 networks and 2 ho

题目

The 213.115.77.0 network was subnetted using a /28 subnet mask. How many usable subnets and host addresses per subnet were created as a result of this?

A. 2 networks with 62 hosts

B. 6 networks with 30 hosts

C. 16 networks and 16 hosts

D. 62 networks and 2 hosts

E. 14 networks and 14 hosts

F. None of the above

相似考题

1.有如下类定义： class Point{ private： static int how_many； }； ______how_many=0； 要初始化Point类的静态成员how_many，在下画线处应填入的内容是A．intB．static intC．int Point::D．static int Point::

2.有如下类定义： class Point{ private： static int how_many； }； ______how_many=0； 要初始化Point类的静态成员how_many，下划线处应填入的内容是A．intB．static intC．int Point: :D．static int Point

3.You must segment your internal ／24 network into a minimum of 12 subnets, each containing a minimum of 12 hosts. Which network mask do you use?()A. /26B. /27C. /28D. /29

4.有如下类定义：\nclassPoint{\nprivate;\nstaticinthow_many;\n};\n___________how_many=0;\n要初始化Point类的静态成员how_many，下划线处应填入的内容是A、ingB、staticintC、intPoint::D、staticintPoint::

参考答案和解析
正确答案：F
F 解析：Explanation:
A class C subnet with a 28 bit mask requires 4 bits for the network address, leaving 4 bits for host addresses. Using the 2n-2 formula (24-2 in this case) we have 14 host addresses and 16 network addresses.

Incorrect Answers:
A. This would be the result of a /26 network mask
B. This would be the result of a /27 network mask
C. Remember we need to always subtract two for the network and broadcast addresses, so this answer is incorrect.
D. This would be the result of a /30 network mask.
更多“The 213.115.77.0 network was subnetted using a ／28 subnet mask. How many usable subnets an ”相关问题

  • 第1题：

    You have been assigned the ／24 network and need to segment it into at least 60 subnets. Which network mask meets this requirement?()

    A. /27

    B. /28

    C. /29

    D. /30


    参考答案：D

  • 第2题：

    You have been assigned the 66.96.130.0／24 network and need to segment ito at least 60 subnets. Which network mask meets this requirement?()

    A. /27

    B. /28

    C. /29

    D. /30


    参考答案：D

  • 第3题：

    How many subnets can be gained by subnetting 172.17.32.0／23 into a ／27 mask, and how many usable host addresses will there be per subnet?()

    A. 8 subnets, 31 hosts

    B. 8 subnets, 32 hosts

    C. 16 subnets, 30 hosts

    D. 16 subnets, 32 hosts

    E. A Class B address can‘t be subnetted into the fourth octet.


    参考答案：C

  • 第4题：

    有如下类定义： class Point{ private： static int how_many； }； ___________how_many=0； 要初始化Point类的静态成员how_many，下画线处应填入的内容是( )。

    A.int

    B.static int

    C.int Point：：

    D.static int Point：：


    正确答案：C
    本题考查静态数据成员，静态数据成员可以初始化，但只能在类体外进行初始化，其一般形式为：数据类型类名：：静态数据成员名=初值。所以本题答案为C。

  • 第5题：

    Followingticketconsistsofaproblemdescriptionandexistingconfigurationonthedevice.

    Figure1

    Figure2

    TroubleTicketStatement

    Client1isnotabletoreachtheWebServer.InitialtroubleshootingshowsthatDSW1canpingtheFa0/1interfaceofR4butnotthes0/0/0/0.34interface.

    ConfigurationonDSW1

    routereigrp10

    network10.1.4.40.0.0.0

    network10.2.1.10.0.0.0

    network10.2.4.130.0.0.0

    noauto-summary

    ConfigurationonDSW2

    routereigrp10

    network10.1.4.80.0.0.0

    network10.2.2.10.0.0.0

    network10.2.4.140.0.0.0

    noauto-summary

    ConfigurationonR4

    routereigrp10

    network10.1.4.50.0.0.0

    noauto-summary

    redistributeospf1metric1001025511500route-mapEIGRP_to_OSPF!

    routerospf1

    network10.1.1.80.0.0.0area34

    redistributeeigrp10subnets!

    route-mapEIGRP→OSPF

    matchipaddress1!

    access-list1permit10.0.0.00.255.255.255

    access-list1permit209.0.0.00.255.255.255

    Whatisthesolutionofthefaultcondition？（）


    参考答案：B

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