The CEO ________ that Tony was appointed as the manager of the marketing department in today's meeting.A、announcedB、declinedC、attended

Examine the structure of the EMPLOYEES and DEPARTMENTS tables:EMPLOYEESEMPLOYEE_ID NUMBERDEPARTMENT_ID NUMBERMANAGER_ID NUMBERLAST_NAME VARCHAR2(25)DEPARTMENTSDEPARTMENT_ID NUMBERMANAGER_ID NUMBERDEPARTMENT_NAME VARCHAR2(35)LOCATION_ID NUMBERYou want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?（）

A. SELECT last_name, department_name, location_id FROM employees , department ;

B. SELECT employees.last_name, departments.department_name, departments.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;

C. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE manager_id = manager_id;

D. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;

Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?（）

A. SELECT last_name, department_name FROM employees , departments(+);

B. SELECT last_name, department_name FROM employees JOIN departments(+);

C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments d

D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E. SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);

F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);

This is the first time that a woman has been______to the post.

A．granted

B．praised

C．pointed

D．appointed

阅读以下说明和Java代码，将应填入(n)处的字句写在对应栏内。

[说明]

本程序的功能是给公司的员工Tom，Jack，Green增加薪水。三人的职位分别是programmer， Manager，CEO。

程序由6个类组成：WorkerTest是主类，programmer，Manager，CEO三个类，薪水增加的规则是 programmer的涨幅是5%；Manager的是10%；CEO也是Manager，但是它除了有Manager的涨幅，还有1000元的bonus。接口SalaryRaise提供了一个增加薪水的方法raise()。

[java程序]

public class WorkerTest {

public WorkerTest( ) {}

public static void main( String[] args) {

Programmer programmer = new Programmer( "Tom" ,3000);

Manager manager = new Manager( "Jack" ,4000);

CEO ceo = new CEO( "Green" ,4000);

Worker [] worker = new Worker[3];

programmer, raise( );

manager, raise( );

ceo. raise( );

worker[0] = programmer;

worker [1] = manager;

worker[2] = ceo;

for ( int i = 0 ;i ＜ worker, length; i + + ) {

System. out. prinfln (" Name:" + worker [i]. getName ( ) +" \ tSalary:" + worker [i]. getSalary ());

public interface SalaryRaise { void raise( ); }

public class Worker {

public String name;

public double (1);

public Worker( ) {}

public String getName( ) {return name;}

public void setName( String name) {this. name = name;}

public double getSalary( ) {return salary;}

public void setSalary(double salary) { this. salary = salary; }

}

public class Programmer extends Worker implements (2) {

public Programmer( ) {}

public void raise( ) {

double pets=0.05;

double sala = this. getSalary( ) * (1 + pers);

this. setSalary (sala);

public Programmer( Siring name, double salary) t

this. name = name;

this. salary = salary;

public class Manager extends (3) implements SalaryRaise {

public Manager( ) { }

public Manager(String name, double salary) {

this. name = name;

this. salary = salary;

}

public void raise( ) {

double pets = 0.1;

double sala = this. getSalary() * (1 + pers);

this. setSalary(sala);

}

}

public class CEO extends Manager implements SalaryRaise {

public CEO() {}

public CEO( String name,double salary) {

this. name = name;

this. salary = salary;

}

public void raise( ) {

double bonus = 1000;

(4);

double sala = this. getSalary( );

(5);

this. setSalary(sala);

}

}

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?（）

A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);

B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;

给出下面不完整的类代码，则横线处的语句应该为( )。 class Person { String name，department； int age； public Person (Strings) {name=s；} public Person (String s，int

A．{name=s；age=a;} public Person (String n，String d，intA){ __________ department=d； } }A)Person (n，A)；

B．this (Person(n，A))；

C．this(n，A)；

D．this(name，age)；