Your company has a main office and two branch offices. Domain controllers in the main office host an Active Directory-integrated zone.The DNS servers in the branch offices host a secondary zone for the domain and use the main office DNS servers as the DNS

题目

Your company has a main office and two branch offices. Domain controllers in the main office host an Active Directory-integrated zone.The DNS servers in the branch offices host a secondary zone for the domain and use the main office DNS servers as the DNS Master servers for the zone. Each branch office has an application server. Users access the application server by using its fully qualified domain name. You need to ensure that users in the branch offices can access their local application server even if the WAN links are down for three days.What should you do?()

A. Increase the Expires After setting to 4 days on the Start of Authority (SOA) record for the zone.

B. Increase the Refresh Interval setting to 4 days on the Start of Authority (SOA) record for the zone.

C. Configure the Zone Aging / Scavenging Properties dialog box to enable Scavenge stale resource records, and set the Refresh setting to 4 days.

D. Configure the Zone Aging / Scavenging Properties dialog box to enable Scavenge stale resource records, and set the No-refresh interval setting to 4 days.


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  • 第1题:

    下列写法正确的是( )。

    A.main () { int i=3,j; j=5 }

    B.main() { int i=3;

    C.main ()

    D.main() {;}


    正确答案:D
    解析:本题考查语句的基本构成。选项A)中j=5后面少了一个分号:选项B)中少了“}”;选项C)不是一个完整的函数定义格式,一个完整的函数定义格式还包括一对花括号:选项D)正确,是一个空语句。

  • 第2题:

    下列写法正确的是( )。

    A.main() { int i=3,j; j=5 }

    B.main() { int i=3;

    C.main()

    D.main() {;}


    正确答案:D
    解析:本题考查语句的基本构成。选项A)中j=5后面少了一个分号;选项B)中少了“}”;选项C)不是一个完整的函数定义格式,一个完整的函数定义格式还包括一对花括号;选项D)正确,是一个空语句。

  • 第3题:

    有以下程序

    main()

    {char *s[]={"one","two","three"},*p;

    p=s[1];

    printf("%c,%s\n",*(p+1),s[0]);

    }

    执行后输出结果是

    A.n,two

    B.t,one

    C.w,one

    D.O,two


    正确答案:C
    解析:本题首先定义了一个有3个元素的指针数组s,并通过赋值使s[0]指向字符串“one”,s[1]指向字符串“two”,s[2]指向字符串“three”,然后通过赋值语句“p=s[1]”,使p指向了字符串“two”,故“*(p+1)”就是字符“w”。

  • 第4题:

    运行名为main的菜单程序的命令是( )。

    A.DO main

    B.DO main.mpr

    C.DO main.mnx

    D.以上都不对


    正确答案:B

  • 第5题:

    有以下程序: main() { char *S[]={"one","two","three"},*p; p=s[1]; printf("%c,%s\n", *(p+1), s[0]); } 执行后输出结果是( )。

    A.n,two

    B.t,one

    C.w,one

    D.o,two


    正确答案:C
    解析:本题首先定义了一个有3个元素的指针数组s,并通过初始化列表使s[0]指向字符串“one”,s[1]指向字符串“two”,s[2]指向字符串“three”,然后通过赋值语句p=s[1],使p指向了字符串“two”,故*(p+1)就是字符‘w’。所以,C选项为所选。

  • 第6题:

    【单选题】下面程序的输出是。 main() {enum team {my,your=4,his,her=his+10}; printf("%d%d%d%dn",my,your,his,her);}

    A.0 1 2 3

    B.0 4 0 10

    C.0 4 5 15

    D.l 4 5 15


    DDBBCC C语言对枚举的定义规定:在枚举中声明的各个枚举元素,如果没有明确指出某个枚举元素的值,它的上一个元素存在并有明确值的情况下,这个枚举元素的值为其上一个元素的值+1。在本题中,没有明确说明枚举元素em3的值,则em3=em2+1=1+1=2,进而可知,在printf()打印函数中,要打印的数组元素是aa[3]、aa[1]、aa[2],因此最后的打印结果应当为“DDBBCC”。