更多“Which four are valid Oracle constraint types? () ”相关问题
  • 第1题:

    Giventhetwosecurityconstraintsinadeployment&ensp

    Giventhetwosecurityconstraintsinadeploymentdescriptor:

    101.<security-constraint>

    102.<!--acorrecturl-patternandhttp-methodgoeshere-->

    103.<auth-constraint><role-name>SALES</role-name></auth-.<auth-constraint>

    104.<role-name>SALES</role-name>

    105.</auth-constraint>

    106.</security-constraint>

    107.<security-constraint>

    108.<!--acorrecturl-patternandhttp-methodgoeshere-->

    109.<!--Insertanauth-constrainthere-->

    110.</security-constraint>

    Ifthetwosecurityconstraintshavethesameurl-patternandhttp-method

    whichtwo insertedindependentlyatline109,willallowuserswithrolenamesofeitherSALESorMARKETINGtoaccessthisresource?()


    参考答案:B, D

  • 第2题:

    Youareresponsibleforadatawarehouseapplicationthatusesrecordsfromanexternaltabletoupdateoneofthedimensiontablesperiodically.Therecordsintheexternaltablemaycontaindatafornewrowsinthedimensiontable,orforupdatestoitsexistingrows.WhichtypeofSQLcommandwouldyouusetotransferthedatafromtheexternaltabletothedimensiontableasefficientlyaspossible?()

    A.MERGE

    B.SELECT…CROSSJOIN

    C.INSERTALL…SELECT

    D.CREATEVIEW…CONSTRAINT


    参考答案:A

  • 第3题:

    The neighborhood boys like to play basketball on that( )lot.

    A.vague
    B.vacant
    C.vain
    D.valid

    答案:B
    解析:
    句意:附近的男孩子们喜欢在那块空地上打篮球。A.vague意为“模糊不清的,不明确的”,C.vain指“徒然的;虚荣的”,D.valid指“正当的,有效的”。这三个词都不合题意,只有vacant是“空着的,无人的”意思,a vacant lot就是“空地”。

  • 第4题:

    Which view shows all valid values for the NLS_LANGUAGE, NLS_SORT, NLS_TERRITORY,and NLS_CHARACTERSET parameters?()

    A. V$VALID_NLS_VALUES

    B. NLS_VALID_VALUES

    C. NLS_VALUE_OPTIONS

    D. V$NLS_VALUE_OPTIONS

    E. V$NLS_VALID_VALUES


    参考答案:E

  • 第5题:

    在Oracle中,()程序包中提供了所有预定义的异常的定义。

    A.DBMS_STANDARD

    B.DBMS_STD

    C.DBMS_SQL

    D.DBMS_TYPES


    参考答案:D

  • 第6题:

    下列给字符串二维数组进行赋值的语句中,错误的是()。

    A.String s[ ] [ ] = new String [ ] [ ] { { “One “ , “ Two “ }, { “ Three “ , “ Four “ } } ;

    B.String s[ ] [ ] = { { “ One “ , “Two “},{ “ Three “ , “ Four “ } } ;

    C.String s[ ] [ ] = new String [ ] [ ] { { “Zero”} , { “ One ” , “Two” , “ Three” , “ Four” } } ;

    D.String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;


    String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;