●Traditional structured analysis techniques focus upon the flow of(71)within a system Object-oriented analysis emphasizes the building of real-world models It examines requirements from the perspective of the classes and objects found in the vocabulary

题目

●Traditional structured analysis techniques focus upon the flow of(71)within a system Object-oriented analysis emphasizes the building of real-world models It examines requirements from the perspective of the classes and objects found in the vocabulary of the(72)domain

Traditional system design method emphasizes the proper and effective structure of a complex systemObject-oriented design method encompasses the process of object-oriented decomposition and a(73)for depicting both logical and physical as well as static and dynamic models of the system under design

Object-oriented programming is a method of implementation in which programs are organized as cooperative collections of objects, each of which represents an(74)of some class, and whose classes are all members of a hierarchy of classes united via(75)relationships

(71)A.control B.program C.data D.reference

(72)A.problem B.solution C.data D.program

(73)A.mark B.picture C.symbol D.notation

(74)A.instance B.example C.existence D.implementation

(75)A.control B.inheritance C.inference D.connection

相似考题

1.下面程序段的输出结果为 public class Test { int a，b； Test() { a=100； b=200； } Test(int x,int y) { a=x； b=y； } public static void main(String args[]) { Test Obj1=new Test(12,45)； System．out．println(”a=”+Obj 1．a+” b=”+Obj 1．b); Test Obj2=new Test()； System．out．println(”a=”+Obj 2．a+” b=”+Obj 2．b); } }A．a=100 b=200 a=12 b=45B．a=12 b=45 a=100 b=200C．a=12 b=200 a=100 b=45D．a=100 b=45 a=12 b=200

2.下列程序段的输出结果是______。 public class Test{ int a,b； Test( ){ a=100； b=200； } Test(int x,int y){ a=X； b=y； } public static void main(String args[ ]){ Test Obj1=new Test(12,45)； System.out.println("a="+Obj1.a+"b="+Obj1.B)； Test Obj2=new Test( )； System.out.println("a="+Obj1.a+"b="+Obj1.B)； } }A．a=100 b=200 a=12 b=45B．a=12 b=45 a=100 b=200C．a=12 b=200 a=100 b=45D．a=100 b=45 a=12 b=200

3. The survival of civilization as we know it is _____ threat.(A) within (C) towards(B) under (D) upon

4.下面程序段的输出结果为( )。 publicclass Test { int a,b； Test() { a=100； b=200； } Test(intx,inty) { a=X； b=y； } publicstaticvoidmain(Stringargs[]) { TestObj1=newTest(12,45)； System.out.println("a="+Obj1.a+" b="+Obj1.b)； TestObj2=newTest()； System.out.println("a="+Obj2.a+"b="+Obj2.b)； } }A．a=100b=200 a=12 b=45B．a=12 b=45 a=100b=200C．a=12 b=200 a=100b=45D．a=100b=45 a=12 b=200

更多“●Traditional structured analysis techniques focus upon the flow of(71)within a system Obj ”相关问题

  • 第1题：

    Although the bulk of industry resources and energies have focused on developing the fastest(71)or slickest(72)more and more mindshare is turning to the evolution of the computer interface. Advancements in the areas of input devices,(73)processing and vitual reality could lead to fundamental changes in the way human and computer interact. The technological battlefield of the future will be adding layers between the user and the raw machine to make the(74)as invisible as possible.(75)represents the next evolutionary step for the interface.

    A．microprocessor

    B．format

    C．structure

    D．procedure


    正确答案：A

  • 第2题：

    有如下程序； public class MethTest { static int Varl=100； int Var2=200； public static void main(String args[]) { Varl=10； MethTest Obj1=new MethTest()； MethTest Obj2=new MethTest()； Obj1.Varl++； System.out.println(Objl.Varl)； Obj2.Varl++； System.out.println(Obj2.Varl)； MethTest.Varl++； System.out.println(Objl.Varl)； Obj1.Var2++； System.out.println(Obj1.Var2)； Obj2.Var2++； System.out.println(Obj2.Var2)； } } 程序的运行结果为( )。

    A．11 12 13 201 201

    B．101 102 103 201 201

    C．11 12 13 201 202

    D．10 10 10 201 201


    正确答案：A
    解析：本题考查实例成员和类成员用法的不同。在给出的程序中，声明一个类变量Var1、实例变量Var2和类方法main。在类方法main中访问类变量Var1和实例变量Var2，在main方法中还实例化了MethTest类的两个对象Obi1和Obi2，通过这两个对象访问类变量和实例变量。我们知道，可以通过类名直接访问类变量，而且，所有实例对象将共享同一个类变量，每个实例对象对类变量的改变都会直接影响到其他实例对象，但一个对象对实例变量的改变不会影响其他实例对象。因此Var1的值每次都会增1，并且保持已经改变的值，Var2的值由于是分别调用，故值并不会改变。

  • 第3题：

    All three types of cryptography schemes have unique function mapping to specific.For example,the synunetric key（71）approach is typically used for theencryption of data providmg（72）,whereas asymmetric key cryptography is maidy used in key（73）and noruepudiation,thereby providing confidentiality and authentication.The hash（74）（noncryptic）,on the other hand,does not provide confidentiality but provides messageintegrity,and cryptographic hash algorithms provide message（75）and identity of peers during transport over insecure channels.
    请作答74题。

    A.Algorithm
    B.Secure
    C.structure
    D.encryption

    答案：A
    解析：

  • 第4题：

    The stages within the development phase of the software life cycle are ( 71 ).

    A.design, analysis, implementation, and testing

    B.analysis, design, implementation, and testing

    C.analysis, design, testing, and implementation

    D.design, analysis, testing, and implementation


    正确答案：C

  • 第5题：

    Certificates are（71）documents attesting to the（72）of a public key to an individual or other entity.They allow verification of the claim that a given public key does in fact belong to a given individual.Certificates help prevent someone from using a phony key to（73）someone else.In their simplest form,certificates contain a public key and a name.As commonly used,a certificate also contains an（74）date,the name of the CA that issued the certificate,a serial number,and perhaps other information.Most importantly,it contains the digital（75）of the certificate issuer.The most widely accepted format for certificates is X.509,thus,certificates can be read or written by any application complying with X.509.

    A.text
    B.data
    C.digital
    D.structured

    答案：C
    解析：
    数字认证是一种证明个人或其他机构
    拥有
    某一公开密钥的
    数字
    文件。数字认证用于确定某一给定的公钥是否确实属于某个人或某个机构。数字认证有助于防止有人
    假冒
    别人的秘钥。形式最简单的数字认证包含一个公钥和一个用户名。通常，数字认证还包括
    有效期
    ，发证机关名称，序列号，也许还包含其他信息。最重要的是，它包含了发证机关的数字
    签名
    。最普遍公认的数字认证标准是X.509国际标准，任何遵循X.509的应用程序都能读写遵循X.509标准的数字认证。

  • 第6题：

    All three types of cryptography schemes have unique function mapping to specific．For example, the symmetric key approach （71） is typically used for the encryption of data providing（72）, whereas asymmetric key cryptography is maidy used in key（73）and nonrepudiation, thereby providing confidentiality and authentication． The hash（74）（noncryptic）, on the other hand, does not provide confidentiality but provides message integrity, and cryptographic hash algorithms provide message（75）and identity of peers during transport over insecure channels．

    A.Algorithm
    B.Secure
    C.structure
    D.encryption

    答案：A
    解析：
    略

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