As a result of these advantages, optical fiber communication systems are widely employed for applications (96)major telecommunications backbone (97) to Ethernet systems, broadband distribution, and general data networking.A. including 包含 B. ranging from从。

题目

As a result of these advantages, optical fiber communication systems are widely employed for applications (96)major telecommunications backbone (97) to Ethernet systems, broadband distribution, and general data networking.

A. including 包含 B. ranging from从。。。排列 C. consisting of由。。。组成 D. composing of 构成 A. structure 结构,体系 B. networking 网络化 C. infrastructure基础建设基础设施 D. connection 连接


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  • 第1题:

    Acustomer’sdatacenterhasallPOWER4+systems,andtheyplantoaddthreenewp5-570systems.Theywillbepurchasinganew7310-CR2HMCtosupportthePOWER5systems.WhatisakeyrequirementthattheyneedtoplanforwiththenewHMC?()

    A.Adesk,asitnotrackmountable

    B.EthernetconnectionstothePOWER5systems

    C.SerialconnectionstothePOWER5systems

    D.USBconnectionsforthekeyboardandmouse


    参考答案:B

  • 第2题:

    9、阅读以下程序,填写运行结果________________. def f(n): s=str(n) result='' for i in range(0,len(s)): result=s[i]+result return result print(f(345))


    14

  • 第3题:

    下面的方法,当参数值为2的时候返回值是多少 public int getValue(int i) { int result = 0; switch (i) { case 1: result = result + i; case 2: result = result + i * 2; case 3: result = result + i * 3; } return result; }

    A.10

    B.8

    C.6

    D.4

    E.2

    F.0


    错误

  • 第4题:

    The shutters stood( ),and through one of the newly-washed windows I caught the light of a fire.

    A.wide
    B.straight
    C.upright
    D.widely

    答案:A
    解析:
    考查副词辨析。百叶窗全开着,透过刚擦完的玻璃,我看到了一束火光。

  • 第5题:

    【单选题】在程序中有语句_________时,须在程序开始使用宏命令#include<math.h>。

    A.printf(”Result:%fn”,sqrt(a));

    B.printf(”Result: sqrt(a)%fn”, a);

    C.printf(” sqrt(% f)n”, a);

    D.printf(” Result: sqrt(% f)n”, a);


    正确

  • 第6题:

    下面的方法,当参数值为2的时候返回值是多少 1. public int getValue(int i) { 2. int result = 0; 3. switch (i) { 4. case 1: 5. result = result + i; 6. case 2: 7. result = result + i * 2; 8. case 3: 9. result = result + i * 3; 10. } 11. return result; 12. }

    A.10

    B.8

    C.6

    D.4

    E.2

    F.0


    错误