Functional view considers language as a communicative tool, whose main use is to build up and maintain social relations between people. ()此题为判断题(对，错)。

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Functional view considers language as a communicative tool, whose main use is to build up and maintain social relations between people. ()

此题为判断题(对，错)。

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4.下列程序段的输出结果为()。includemain(){static char a[]="language";char*p;p=a;for下列程序段的输出结果为( )。 #include＜stdio.h＞ main() { static char a[]="language"； char*p； p=a； for(p=a;p＜a+8;p+=2) putchar(*p)； }A．1B．4C．9D．0

更多“Functional view considers language as a communicative tool, whose main use is to build up and maintain social relations between people. () ”相关问题

  • 第1题：

    SOX is an alternative syntax for(71). It is useful for reading and creating XML content in a text editor. It is then easily transformed into proper XML. SOX was created because developers can spend a great deal of time with raw XML. For many of us, the popular XML(72)have not reached a point where their tree views, tables and forms can completely substitute for the underlying.(73)language. This is not surprising when one considers that developers still use a(74)view, albeit enhanced, for editing other languages such as Java. SOX uses(75)to represent the structure of an XML document, which eliminates the need for closing tags and a number of quoting devices. The result is surprisingly clear.

    A．SOA

    B．UDDI

    C．XML

    D．Web Service


    正确答案：C

  • 第2题：

    下列程序段的输出结果为()。 include main() {static char a[]="language"; char*p; p=

    下列程序段的输出结果为( )。

    #include＜stdio.h＞

    main()

    { static char a[]="language";

    char*p;

    p=a;

    for(p=a;p＜a+8;p+=2)

    putchar(*p);

    }

    A．language

    B．lnug

    C．有语法错误

    D．lang


    正确答案：B
    解析：本程序首先定义了静态字符数组a，然后将指针p指向数组a的首地址。第1次for循环，p=a，p指向数组的第1个元素，*p是取指针p所指地址的内容，输出1；第2次for循环， p=p+2，则p指向数组的第3个元素，*p是取指针p所指地址的内容，输出n；第3次for循环，p=p+2，则p指向数组的第5个元素，*p是取指针p所指地址的内容，输出u；第4次for循环，p=p+2，则p指向数组的第7个元素，*p是取指针p所指地址的内容，输出g，结束循环。

  • 第3题：

    用所给的词和词组写出符合逻辑的句子。 your/sure/between/I am/will help/present visit/economic and trade/promote/relations/our two countries
    I am sure your present visit will help promote economic and trade relations between our two countries.
    略

  • 第4题：

    下列程序段的输出结果为()。includemain(){static char a[]="language"; char*p; p=a;

    下列程序段的输出结果为( )。 #include＜stdio.h＞ main() { static char a[]="language"； char*p； p=a； for(p=a;p＜a+8;p+=2) putchar(*p)； }

    A．language

    B．lnug

    C．有语法错误

    D．lang


    正确答案：B
    解析： 本程序首先定义了静态字符数组a，然后将指针p指向数组a的首地址。
    第1次for循环，p=a，p指向数组的第1个元素，*p是取指针p所指地址的内容，输出1；第2次for循环，p=p+2，则p指向数组的第3个元素，*p是取指针p所指地址的内容，输出n；第3次for循环，p= p+2，则p指向数组的第5个元素，*p是取指针p所指地址的内容，输出u；第4次for循环，p=p+2，则p指向数组的第7个元素，*p是取指针p所指地址的内容，输出g，结束循环。

  • 第5题：

    下列程序段的输出结果为( )。 include main() { static char a[]="language"; char *p;

    下列程序段的输出结果为( )。 #include＜stdio.h＞ main() { static char a[]="language"; char *p; p=a; for(p=a;p＜a+8;p+=2) putchar(*p); }

    A．language

    B．lnug

    C．有语法错误

    D．lang


    正确答案：B
    解析：本程序首先定义了静态字符数组a，然后将指针P指向数组a的首地址。第1次for循环，p=a，p指向数组的第1个元素，*p是取指针P所指地址的内容，输出1；第2次for循环，p=p+2，则p指向数组的第3个元素，*p是取指针p所指地址的内容，输出n；第3次for循环，p=p+2，则p指向数组的第5个元素，*p是取指针p所指地址的内容，输出u；第4次for循环，p=p+2，则p指向数组的第7个元素，*p是取指针p所指地址的内容，输出g，结束循环。

  • 第6题：

    out of 13)__________ people.


    错误

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