The teacher divides the whole class into pairs. Every student works with his or her partner, and all the pairs work at the same time, it is sometimes call ________. With pairs of students speaking in turn in front of the class is called _______.A.simultan

题目

The teacher divides the whole class into pairs. Every student works with his or her partner, and all the pairs work at the same time, it is sometimes call ________. With pairs of students speaking in turn in front of the class is called _______.

A.simultaneous pairwork

B.public or open pairwork“

C.public or open pairwork

D.simultaneous pairwork“


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  • 第1题:

    Teacher:Where is Mike this morning?

    Student:He's got a cold.

    Teacher:______

    A、He is absent.

    B、What's the matter with him?

    C、Just tell him to take it easy.

    D、What? Where is he?


    参考答案:C

  • 第2题:

    在视频中,父类Person、子类Student和Teacher,都必需定义whoAmI()方法。


    D

  • 第3题:

    在项目中已经建立了一个JavaBean,其类为bean.Student,该Bean具有name属性,则下面标签用法正确的是()。

    A.<jsp:useBean id=”student” class=”Student” scope=”session”></jsp:useBean>

    B.<jsp:useBean id=”student” class=”Student” scope=”session”/>

    C.<jsp:useBean id=”student” class=”bean.student” scope=”session”></jsp:useBean>

    D.<jsp:getProperty name=”name” property=”student”/>


    C

  • 第4题:

    从Student类和Teacher类多重派生Graduate类


    D

  • 第5题:

    【单选题】9、在项目中已经建立了一个JavaBean,其类为bean.Student,该Bean具有name属性,则下面标签用法正确的是()。

    A.<jsp:useBean id="student" class="Student" scope="session"></jsp:useBean>

    B.<jsp:useBean id="student" class="bean.Student" scope="session"> </jsp useBean>

    C.<jsp:useBean id="student" class="Student" scope="session"/>

    D.<jsp:getProperty name="name" property="student"/>


    D 在风险管理理论和方法中,在多数情况下是以离散形式来定量表示风险的发生概率及其损失,因而风险量R相应地表示为:R=∑pi.qpi。式中,i=1,2,……,n,表示风险事件的数量。题中风险量=10%×18+15%×10+20%×8=4.9(万元)。

  • 第6题:

    【单选题】下面程序的输出是。 main() {enum team {my,your=4,his,her=his+10}; printf("%d%d%d%dn",my,your,his,her);}

    A.0 1 2 3

    B.0 4 0 10

    C.0 4 5 15

    D.l 4 5 15


    DDBBCC C语言对枚举的定义规定:在枚举中声明的各个枚举元素,如果没有明确指出某个枚举元素的值,它的上一个元素存在并有明确值的情况下,这个枚举元素的值为其上一个元素的值+1。在本题中,没有明确说明枚举元素em3的值,则em3=em2+1=1+1=2,进而可知,在printf()打印函数中,要打印的数组元素是aa[3]、aa[1]、aa[2],因此最后的打印结果应当为“DDBBCC”。