Mary: I'm sorry, but I can't seem to find that tape you lent me. I must have lost it.Susan: Oh no! _________.Mary: But don't worry. I'll buy you a new one.A. Don't do thatB. What a shameC. Don't say thatD. How pity it is

题目

Mary: I'm sorry, but I can't seem to find that tape you lent me. I must have lost it.

Susan: Oh no! _________.

Mary: But don't worry. I'll buy you a new one.

A. Don't do that

B. What a shame

C. Don't say that

D. How pity it is


相似考题
更多“Mary: I'm sorry, but I can't seem to find that tape you lent me. I must have lost ”相关问题
  • 第1题:

    Will you show me how to use this software?()

    A. Sure. You'll master it in no time.

    B. You are welcome.

    C. Sorry, I'm too late for it.


    参考答案:A

  • 第2题:

    —_______ I return the book to the library this week?— No, you _______.You can keep it until the end of this month.

    A.Must; needn’t

    B.Can; can’t

    C.May; mustn’t

    D.Can; mustn’t


    答案:A

  • 第3题:

    --Sorry, I′m late.
    --That′ s OK. You′ re here that′ s what____________.

    A.does
    B.works
    C.stays
    D.counts

    答案:D
    解析:
    考查固定搭配。that’s what counts表示这才是最重要的。句意为“——抱歉,我迟到了。——没关系,你来才是最重要的。”

  • 第4题:

    —Mary, can I use your computer now? —(). It doesn’t work.

    A、That’s all right

    B、I’m afraid not

    C、You’re welcome

    D、It doesn’t matter


    参考答案:B

  • 第5题:

    有如下程序段#include "stdio.h"#include "string.h"#define N 10#define M 10char *find(char(*a)[M],int n){ char *q;int i; q=a[0]; for(i=0;i<n;i++) if(strcmp(a[i],q)<0)q=a[i]; return q;}main(){ char s[N][M]={"tomeetme","you","and","he","china"}; char *p; int n=5; p=find(s,n); puts(p);}则执行后输出的结果为A.he B.and C.you D.tomeetme


    正确答案:B
    在本题中,首先定义了两个宏N和M,大小都为10,然后定义了一个返回指针的函数find,该函数带有两个形参,第一个为字符型的指针数组,第二个为整型变量,在函数体中,首先定义了一个指针变量q,并将形参中指针数组的第一个元素赋值给q,然后执行for循环,在循环体中,首先执行条件判断语句,其条件为strcmp(a[i],q)<0(strcmp函数的作用是比较两字符串的大小,如果相等,则返回0值,如果参数中的第一个字符串大,则返回正值,否则返回负值),如果结果为真,说明指针数组当前元素所指向的字符串比q所指向的字符串小,此时,程序执行将当前指针数组元素赋值给p,最后返回p,通过上面的分析我们可以看出,find函数的作用是找出指针数组中各元素所指向字符串的最小字符串。
    在主函数中,定义了一个二维数组s,并赋了初值,然后定义一个指针变量p,用来存放函数find的返回值。调用函数find的参数分别为s和5,结合形参看find函数,不难知道调用find函数就是找出二维数组s中各字符串中最小的字符串,那么应该为and。此时,指针变量p指向字符串“and”的首地址,然后执行puts(p),完成该字符串的输出。因此,本题正确的答案是B。

  • 第6题:

    --Sorry, I′m late.
    --That′s OK. You′re here that′s what ______

    A.does
    B.works
    C.stays
    D.counts

    答案:D
    解析:
    考查固定搭配。that’s what counts表示这才是最重要的。句意为“——抱歉,我迟到了。——没关系,你来才是最重要的。”