A technique that can be used to measure the total income of a project compared to the total moneys expended at any period of time is:A . return on investment (ROI)B . net present value (NPV)C . discounted cash flow (DCF)D . B and CE . All of the above.

题目

A technique that can be used to measure the total income of a project compared to the total moneys expended at any period of time is:

A . return on investment (ROI)

B . net present value (NPV)

C . discounted cash flow (DCF)

D . B and C

E . All of the above.

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更多“A technique that can be used to measure the total income of a project compared to the tota ”相关问题

  • 第1题：

    对下面的个人所得税程序中满足语句覆盖测试用例的是()

    If(income800)taxrate=0;

    elseif(income=1500)taxrate=0.05;

    elseif(income2000)taxrate=0.08;

    elsetaxrate=0.1;

    A、income=(800,1500,2000,2001

    B、"income=(800,801,1999,2000)"

    C、"income=(799,1499,2000,2001)"

    D、"income=(799,1500,1999,2000)"


    正确答案:D

  • 第2题：

    1 can't put up with my neighbor's noise any longer;it's driving me mad.

    A:tolerate
    B:generate
    C:reduce
    D:measure

    答案：A
    解析：
    我再也不能忍受邻居的噪音，那快让我疯了。put up with：忍受，tolerate和它意思相近 generate；产生；reduce：减少，缩小；measure：测量，估计。

  • 第3题：

    对下面的计算个人所得税程序中，满足判定覆盖的测试用例是（)。 if （income＜800) taxrate=0; else if （income＜=1500) taxrate=0.05; else if （income＜2000) taxrate=0.08; else taxrate=0.1;

    A．income=(799, 1500, 1999, 2000)

    B．income=(799, 1501, 2000, 2001)

    C．income=(800, 1500, 2000, 2001)

    D．income=(800, 1499, 2000, 2001)


    A

  • 第4题：

    _________________

    A. ideas B. ambitious C. achievement D. technique


    正确答案：A

  • 第5题：

    technique
    When we talk about a technique, we mean a procedure used in the classroom. Techniques are the tricks in classroom teaching.
    略

  • 第6题：

    【单选题】下面的个人所得税程序中，满足语句覆盖测试用例的输入数据是（） if （income ＜ 800) taxRate= 0; else if （income ＜= 1500) taxRate = 0.05 ; else if （income ＜ 2000) taxRate = 0.08 ; else taxRate= 0.1 ;

    A．income = (800, 1500, 2000, 2001)

    B．income = (800, 801, 1999, 2000)

    C．income = (799, 1499, 2000, 2001)

    D．income = (799, 1500, 1999, 2000)


    D

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